For C I tried setting bn=1/(n^(2) -1) and took the limit to get that it goes to 0. Since bn is not greater than 0 an also converges.
Yes?
If so then I did the same thing for D and got the same answer.
For a. Can I just state that sin is bounded by -1 to 1 and therefore does not exist?
I went to the link you provided. I set bn=sin(1/n) and the limit does not equal 0, and therefore does not converge?
Also the same with b. Since the lim of bn which would be (1 +4/n)^n would also = 1 and not...
Alright, I have my final for Calc 2 on Monday. I am only stuck on two sections of problems because I am terrible at convergence and divergence/alternating series.
I have questions for each one really. They are as follows:
4)
a. Can I simply factor out the alternating series and apply a...