Recent content by bbrudi

Thank you

That's where I'm stuck how do I express that he borrowed $1000 more at 9%? Would it be possibly y + 1000 = 0?

So should the problem look something like this? x + y + z = 25,000 .08x + .09y + .10z = 2,190 x = 1000 + y

Problem: To get the necessary funds for a planned expansion, a small company took out three loans totaling $25,000. Company owners were able to get interest rates of 8%, 9%, and 10%. They borrowed $1000 more at 9% than they borrowed at 10%. The total annual interest on the loans was $2190...