Recent content by behnz06

I don't know. I got the problem wrong too many times. It says that the answer is 1.28m/s. I don't understand how they got it.

V= 2.13km/1.8mpersecond = 1.2 (wrong answer)

v=d/t

I mean 1.18 m per second

Okay now i just tried converting 1.8miles pers second to km/s. Got 1800km/s and did 2.13 over 1800 km and got 1.18km/s

I don't know how to do that lol. would I set the problem up like 2.13km=1.8m/s over 3km?

I know it's not a square. But i believed it was a right angle. thus if I added a triangle just like that t would be a square

By the way its 1.6 km and 1.4 km. And he moves at the rate of 1.8 m/s

My thought process was that the triangle I made (using the 2 sides plus the displacement that I solved) could be seen as a square.lol. Thus, instead of going all around from ABC. AC would be a shortcut. I'm not quite sure if I was able to explain this clearly.

Homework Statement John walks 1.60 north, then turns right and walks 1.40 east. His speed is 1.80 during the entire stroll. If Jane starts at the same time and place as John, but walks in a straight line to the endpoint of John's stroll, at what speed should she walk if she wants to...