Sorry about the notation mistake, having to hold down shift to do all my parentheses must have thrown me off; a mere typo.
Alas, I mixed up what I was doing when typing out my method.
To find f(-3), I found an equation for the line of f'(x) on x: [-3,0]. I found the equation to be y' = -x...
Hey everyone! My name is Ben, I'm a senior in high school working on an BC Calc problem and am having some general questions about it.
The question reads:
Let f be a function defined on the closed interval [-3,4] with f(0) = 3. The graph of f', the derivative of f, consists of one line segment...