Hey guys, so the second one is correct ? This is the integral I figured for the first one:
\int _{0}^{1} -3a+2a^{2}+4a^{3}+6a^{5}da=\frac{7}{6} Edit: there should be an integral symbol in front of the _{0}^{1} , seems it won't render. Sorry! Thanks for your feedbackBibhatsu
Homework Statement
Compute the Work of the following line integrals in the vector field \vec{V}=(2x^{2}-3y;4xy;3x^{2}z)
Homework Equations
For the following lines:
Curve1: \vec{r}(a)=(a,a,a^{2}); \ 0\le a \le 1
Curve2: \vec{r}(a)=(a,a^{2},a); \ 0\le a \le 1
The Attempt at a Solution...