Recent content by Bibhatsu

Hello, I see my mistake. Thank you. Greetings Bibhatsu

Hello,I see my mistake.Thank you. Greetings Bibhatsu

Hey guys, so the second one is correct ? This is the integral I figured for the first one: \int _{0}^{1} -3a+2a^{2}+4a^{3}+6a^{5}da=\frac{7}{6} Edit: there should be an integral symbol in front of the _{0}^{1} , seems it won't render. Sorry! Thanks for your feedbackBibhatsu

Homework Statement Compute the Work of the following line integrals in the vector field \vec{V}=(2x^{2}-3y;4xy;3x^{2}z) Homework Equations For the following lines: Curve1: \vec{r}(a)=(a,a,a^{2}); \ 0\le a \le 1 Curve2: \vec{r}(a)=(a,a^{2},a); \ 0\le a \le 1 The Attempt at a Solution...