Recent content by binjip

Ok, I run a simulation and the results are correct. Thanks.

Homework Statement Hi, Suppose we have a die with 3 colors on it. 4 sides are blue => P(Z=Blue) = 2/3 1 side is green => P(Z=Green) = 1/6 1 side is red => P(Z=Red) = 1/6 I throw it 20 times and have Z=(Z1,..., Z20). Now what is the expected number of "runs"? Run is defined as...

Thank you Ray, I didn't think of it this way, but it seems much clearer now. Ok, so I have 7! / (1!*1!*1!*1!*1!*2!) = 7!/2 = 2520 ways of arranging the 7 balls into 6 bins. There are 6^7 of arranging the balls when there are no conditions. P({1,...5} comes up once and 6 twice) = (7! / 2) /...

Hi Klockan3, ok, suppose I had only 6 turns throwing a die (or as you suggested having only 6 dice). There would be 6*5*4*3*2*1 possible ways of arranging the numbers so that I have each number exactly once. This is 6!. So the result would be 6! / 6^6. Now, I argued that I have an...

Throwing a die 7 times Homework Statement Throw a die 7 times. i) What is the probability that you get number 6 twice and all other outcomes once. (e.g. one possible set of outcomes would be 6, 6, 5, 4, 3, 2, 1) ii) What is the probability that you get all the numbers of a die? (e.g...