Recent content by Bocian

Yes, I just didn't simplfy it yet. This is my first physics lesson so I'm still learning the basics. Our teacher said it would be challenging for us. Thanks for bearing with me on this.

Remove them since are 0?

The initial velocity is both 0. Ok I replaced the + with a - on the left and removed parenthesis around ab

Alright so I got Xb+v0T+(1/2)-(aB)t^2=0+v0T+(1/2)aAT^2

Oh ok my bad. So the final equation will just be something=something?

Or would it just be something =something or xf=something + g(t)?

So would I get something+f(t)=something+g(t)?

Would it be xf-something=xf-something?

So I have to combine both equations to equal time? I'm just confused on how to set them up.

xf=xb+v0t+(1/2)-(aB)t^2-0-v0t-(1/2)aAt2 like this? still not sure how exactly to combine them together to have 1 = sign.

xf=xb+v0t+(1/2)-aBt2=xf=0+v0t+(1/2)aAt2 so like this?

so for cart B: xf=xb+v0t+(1/2)aBt2 and cart A: xf=0+v0t+(1/2)aAt2 Do i need to set them equal to each other now?

Oh ok thanks a lot for that. so i would use: x=x0+v0t+(1/2)at2? What exactly does the 0 mean next to the x and v ? now that i have this how would i go about apply this?

ok would i use: vf^2= vi^2+2ax that's the only one i found with position in it. if so, how would i apply this?

Alright, how would i go about finding this formula? Sorry I'm not really keen on physics lol.