Recent content by bubba640

I actually have the same question I'm working on and went through the steps to solve this problem. I got the top branch right and the bottom keeps turning up to be wrong. Was 3 right for you?

OKAY SO FOR THE FIRST QUESTION WORK = KINETIC ENERGY SOOOO Average impact force x distance traveled = change in kinetic energy f=MA F=22448.9 KG* 490.3=11006695.67 CHANGE IN KINETIC ENERGY= 11006695.67* 88= 968589218.96 IS THIS RIGHT??

PLEASE HELP I'M CLUELESS ON THESE PROBLEMS FOR THIS QUESTION I FOUND B BUT I HAVE NO IDEA ON HOW TO FIND A. A plane weighing 220 kN (25 tons) lands on an aircraft carrier. The plane is moving horizontally at 62 m/s (139 mi/h) when its tailhook grabs hold of the arresting cables. The...

A plane weighing 220 kN (25 tons) lands on an aircraft carrier. The plane is moving horizontally at 62 m/s (139 mi/h) when its tailhook grabs hold of the arresting cables. The cables bring the plane to a stop in a distance of 88 m. (a) How much work is done on the plane by the arresting...