Recent content by BuGzlToOnl

Thank you, I'll talk to him tomorrow. I just wanted to make sure I wasn't doing anything wrong.

I took the natural log of both sides and still got the same answer... ln(.45)=(-24.2t)/181 (-.7985)*181 = (-24.2t) -144.52/-24.2=t 5.9723=t ... that's the answer I got originally and it tells me its not the right answer. gRR~

Question in link, I can't seem to get this one. http://img190.imageshack.us/img190/3941/limith.jpg Everything inside the parenthesis should go to zero and the first part should be 164.54. I then multiply (.55)*(164.54) and set that equal to the original equation. I tried solving for t...

Homework Statement A bungee jumper, whose mass is 98 kg, jumps from a tall building. After reaching his lowest point, he continues to oscillate up and down, reaching the low point two more times in 9.3 s. Ignoring air resistance and assuming that the bungee cord is an ideal spring, determine...

Angles are always in degrees. Angle A + Angle B + Angle C = 180* always for ANY triangle.

Haha I did this problem yesterday for an online quiz, I'll help you out a bit. This is how I did it. The initial velociy is 11 m/s. V_0 = 11 m/s The following equation will give you your x-component of velocity and your y-component of velocity respectively. Which is what you said you needed...

Let me rewrite this your formula for part A is y= (v^2-v[SIZE="1"]0^2)/(2a). After you get your y component your formula for Par B is: t= v-v[SIZE="1"]0/a. t = time a = acceleration y = distance (vertical) And that should give you the answer for the problem. Sorry went through 3 or so...