Recent content by c4795

Thank you very much, I was able to solve it. I can't believe I overlooked that :rolleyes:. And yes you're correct it's r = 2*0.4*sin(6). Thanks again, I'm going to make the TeX a bit nicer and mark the thread resolved :smile:.

Yes, they are: T_{x} = -F_{B} = -L \frac{\mu_{0}I^{2}}{4\pi(0.04-0.04sin(\theta))} with r = 2 * (0.04 - 0.04sin(t)), and T_{y} = -F_{g} = L (1.3\ast 10^{-2}) g I am not sure where to go from here. Does it perhaps involve torque?

I am having trouble understanding how the two equations relate so that I can solve them.

Oh so sorry, the question is to find the current I in each wire, if the cords hang at 6 degrees with the vertical (as in the picture). I'll edit my post.

Magnetic force between two parallel hanging wires (solved) Homework Statement Two long, parallel wires hang by 4.00-cm-long cords from a common axis. The wires have a mass per unit length of 1.30×10−2 kg/m and carry the same current in opposite directions. What is the current in each wire...