okay u right I should have postd my notes, but I wasnt sure so here it is :
1) x positive and y positive
2) x negitive and y positive
3) x positive and y negitive
4) x negitive and y negitive
case 1) p1 → q ,,, x-y ≤ x+y is true ,, for example 6-(+3) ≤ 6 + 3
case 2) p2 → q ...
Discrete Math -- Proof methods
Homework Statement
Prove |x-y| ≤ |x| + |y| for all real numbers x and y (where |x| represents the
absolute value of x, which equals x if x≥0 and equals -x if x<0). prove by cases
Homework Equations
The Attempt at a Solution