Recent content by cantdisclosename

Thank you so much! I figured it out

I came up with the extra two equations I think they are: 1) 3Mg-T1=3Ma 2) Mg-T2=Ma I tried using T1-T2=2Ma (equation 3) along with the two equations I made but still can't figure out acceleration. I tried solving equations 1 and 2 for a and set them equal to each other but it ends up being T1=T2...

τ=Iα T1R-T2R=(2MR^2)(a/R) T1-T2=2Ma a=(T1-T2)/2M Fnet=ma 3Mg-Mg=4Ma 2Mg=(4M)((T1-T2)/2M) and it leads me nowhere. I have no idea what to do because now a is not even a variable in the equation

Homework Statement A pulley of radius, R and moment of inertia, I=2MR^2 is mounted on an axle with negligible friction. Block A, with a mass M, and Block B, with a mass of 3M, are attached to a light string that passes over the pulley. Assuming that the string doesn't slip on the pulley, Answer...