Recent content by Castello

Thank's!

It gets: ##2(i1-i2)-5=0## ##2(i2-i3)+2(i2-i1)+i2-i4=0## ##2(i3-i2)+i3+10=0## ##2i4+Vx+i4-i2=0## ##i1=0## ##i2=-2,5## ##i3=-5## ##i4=-2,5## ##Vx=5v##

Ok, the current source is not in parallel, but in series with the 1ohm resistor, and to check if there is 10v between the current source, it should be on KVL i4 equation. I think i did similar before, as you mentioned for the first loop, but i'll explain how i got there: One equation for each...

So... as the 5A current source is in parallel with the 2ohm resistor, now i can see that it could be transformed in 10v voltage source in series with this resistor. I tried again with KVL and found this: ##-5+2(i1-i3)=0## ##2(i3-i4)+2(i3-i1)+i3-i2=0## ##2i2+Vx+i2-i3=0## ##2(i4-i3)+i4=0##...

Really helped... Thank's! ##5+(VB-VA)/1=VA/2+(VA-VB)/2## ##5/2+(VA-VB)/2=VB/2+(VB-VA)/2## ##VA=7,5V## ##VB=20/3V## By the loops: ##(VA-VB)/2=-i4## ##VB-VA=i2-i4## and relating Vx with i2 and i4: ##Vx=-2,49V## and ##0,83A## through it. So, i4 was on wrong direction, which changed the...

Yes, it's correct. The Vx in the circuit is a voltage source.

Homework Statement Find Vx, as the 5A current source provides 50W to the circuit. Homework Equations ##P = V.I## ##U = R.I## The Attempt at a Solution [/B] At first, as 5A current source provides 50W, by ##p=vi## there should be 10v through it. Then, i applied KVL and found four equations...

Ok, now i see that it's not as general as i was thinking. Thank's! @ehild @gneill

Sorry, i didn't get how to do this. I mean, what i previously understood from source transformation with thevenin theorem is that if i could transform a circuit just in a tension source in series with a resistor, than it would be the Vth and the Rth. Isn't it? This kind of resolution worked in...

Homework Statement Find the Thevenin equivalent at terminals a-b V1 = 70V V2 (dependent) = 4Vo R1 = 10Kohm R2 = 20Kohm Homework Equations ##V=RI## ##1/req = 1/r1 + 1/r2 + ... +1/rn## The Attempt at a Solution Found the current i = 1mA by KVL using Vo = 10ki then did source...

Hello everyone, I'm on the middle of the physics undergrad course. Hope i can help and be helped! greetings