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Awesome, thank you so much! The way I was looking at it was the same as having an equivalent capacitance. The same way you'd find one to "shrink" a circuit to find the resultant potential differences and charges across capacitors. So in summary, a dielectric only affects the capacitance of it's...

So despite the fact that C2 is changing due to a dielectric, C1 wouldn't have to change to compensate?

Also, if I have the equation ΔV = Q1/C1 = Q2/C2 and CNET = C1 + C2, wouldn't this mean that if even one variable changed (as ΔV is constant), the rest would change?

The charge emitted from the battery. When I attempted another answer, I got it right by saying that the charge stays the same. This still confuses me because the voltage shouldn't change, and that being said the charge must change to compensate for the change in capacitance.

Well, the battery emits a voltage that is said to be the same across two capacitors in parallel (or so I was taught and have read), so no the voltage across the two capacitors should not change when a dielectric species is introduced. That being said, doesn't that coincide with what I said...

Homework Statement http://img99.imageshack.us/img99/763/prob45.gif Fig. 1 and 2 show a dielectric slab being inserted between the plates of one of two identical capacitors, capacitor 2. Select the correct answer to each of the statements below (enter I for `increases', D for `decreases', or...