Recent content by cFleming

Sure! 1] The graph goes: < upward to 2 m/s for the first 1 s, and that is where point A is> Then it goes: <upward from 2 m/s to 4 m/s at 2 s for 1s from Point A to 2s (Haven't reached point B yet)> It stays at: <steady acceleration of 4 m/s from s 2-3s and at 2 1/2 s is point...

Ah, I was wrong. At point B the velocity is lying on a horizontal line at 4 m/s. from seconds 2 to 3, the velocity is constant at 4 m/s. So something is not right with my calculations.

Thanks Rap, I figured I would be ridiculed out of the forum. I am nowhere near as intelligent as the average physicist. Your answer flows like a river. :PAnd you are omniscient as well! Point B IS two seconds after point A. You make this seem easy. Physics rocks!

Hello, I'm trying to teach myself basic physics from a book I bought at Davis-Kidd, and I've come across a problem which puzzles me to no end. It's quite simple: It's a problem that uses a graph of a baseball player's change in velocity with time. It labels 3 points of the graph and asks...