Recent content by chaz0426

Oh how I understood your question I thought you needed expressions, as for the actual values I have no clue. I haven't even reached RC and RLC circuits yet in my course and I think I'd need more information.

yeah I know what you mean. I find it handy to have a TI 89 because it can do all that stuff for you however on the flip side you loose your math skills if your too reliant on it. Anyway what I did: I set it up like (s^2 + sqrt(2)*s +1)^-1 = (LC*s^2+RC*s+1)^-1 since fractions even if...

Ooops I didn't see the reply about the superposition problem, thanks!

You did help a lot, thank you so much. I'm a computer engineering major so I don't think I'll have to take circuits II if that is AC analysis and stuff. So I think I'll luck out but it looks hard, is it? I'm use to the software side of things and all this circuit stuff is new. The algebra part...

please someone, the first problem I have finally given up on. I just am confused and cannot find any information on google to answer my question. I don't know what to do for V1 since I am not sure how to set up the equation with a resistor and a voltage source between V1 and the reference node...

Also if someone wouldn't mind verifying my solution to this problem by superposition? http://i615.photobucket.com/albums/tt237/chaz0426/hardSuperpositionproblem.jpg It took me a while but I think I got it. I used KVL for the voltage source and got -12 -3i -3i = 0 so i' = 2Amps for the...

http://i615.photobucket.com/albums/tt237/chaz0426/Problem2.jpg it asks to solve for V1 and V2 using nodal analysis however I'm not sure how to solve this particular one because there is a voltage source and a resistor between the reference node and V1and I'm not sure what to do. Here is what...

I believe I meant 0.140 sorry about that. Yeah I recently discovered about the +'s and -'s thing too my book barely mentions that but I guess it's assumed. Anyway I've given up on that one and just assumed my answer is correct unless someone tells me why its not. I have no idea how to get...

Ok the book says the answer is 0.660Amps but I'm confused as to how. canceling the current source I set up the equation as -3.5 + 10i + 15i = 0 and got i = 0.114A around that one loop and ignored the 5ohm resistor. canceling the voltage source and using current division rules I got the...

Homework Statement http://i615.photobucket.com/albums/tt237/chaz0426/Superpositionproblem.jpg Homework Equations The Attempt at a Solution I know you have to analyze the circuit by turning off each independent current/voltage source and I've done several practice problems in my...