Recent content by Chhung

oh yes! I have to factor that "2" out first thank you!

because I put 2π into the "√" so it turn to √(4π^2) then √( (2k+ mg/l) /4π^2 m) => √( (k+ mg/l) /2π^2 m) isn't it?

Sorry it should be F= m##\ddot x##= -x (2k+mg/l)? f= ω/2 π = √( (k+ mg/l) /2π^2 m)

yes, that X means ##\ddot x## so F= m##\ddot x##= -x (k+mg/l)? f= ω/2 π = √( (k+ mg/l) /4π^2 m) is it all done? I can't go any furhter after this

Homework Statement A small block of mass m is suspended from the top of a box by a mass-less string of length L. Two identical springs, each with spring constant k, extend from the block to the sides of the box, as shown in the diagram to the right. The length of the springs is such that they...