Recent content by ching5633
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Integrating (x^4+x^2)^0.5 form 3^0.5 to -3^0.5
it is [(x^2)*(x^2+1)]^0.5 sorry that I am not expressing this clear- ching5633
- Post #10
- Forum: Calculus and Beyond Homework Help
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Integrating (x^4+x^2)^0.5 form 3^0.5 to -3^0.5
if i substitute x^2=u when x=(3)^0.5 , u=3 when x= - (3)^0.5,u=3 the integral will be from 3 to 3 which is equal to 0- ching5633
- Post #9
- Forum: Calculus and Beyond Homework Help
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Integrating (x^4+x^2)^0.5 form 3^0.5 to -3^0.5
But why i can't calculate in this why ,I just dun know what is going wrong- ching5633
- Post #6
- Forum: Calculus and Beyond Homework Help
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Integrating (x^4+x^2)^0.5 form 3^0.5 to -3^0.5
S(x^4+x^2)^0.5 dx =S(x^2(x^2+1))^0.5 Let x=tan u dx=sec^2(u)du When x=(3)^0.5,u=pi/3 x=-(3)^0.5,u=-pi/3 =S(tan^2(u)(tan^2(u)+1)^0.5*(sec^2(u))du =Ssec^3(u)tan(u)du =Ssec^2(u)d(sec u) =1/3*sec^3(u) By substitution Ans=0- ching5633
- Post #4
- Forum: Calculus and Beyond Homework Help
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Integrating (x^4+x^2)^0.5 form 3^0.5 to -3^0.5
But it is wrong- ching5633
- Post #2
- Forum: Calculus and Beyond Homework Help
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Integrating (x^4+x^2)^0.5 form 3^0.5 to -3^0.5
The Attempt at a Solution Let x=tan u dx=sec^2(u)*du When x=3^0.5,u=pi/3 x=-3^0.5,u=-pi/3 S sec^2(u)d(sec u) =1/3[2^3-2^3]=0- ching5633
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- Forum: Calculus and Beyond Homework Help