Recent content by Chis96
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Undergrad Proving Set Relationships: A-B ⊂ A & (A∩B)c = A∪Bc
Yes, thank you very much sir.- Chis96
- Post #9
- Forum: Set Theory, Logic, Probability, Statistics
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Undergrad Proving Set Relationships: A-B ⊂ A & (A∩B)c = A∪Bc
oh... okay basically what it means is that all elements of A\B are contained inside A.- Chis96
- Post #7
- Forum: Set Theory, Logic, Probability, Statistics
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Undergrad Proving Set Relationships: A-B ⊂ A & (A∩B)c = A∪Bc
No definitions bro, just have to use x to prove it... That's why I'm confused.- Chis96
- Post #5
- Forum: Set Theory, Logic, Probability, Statistics
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Undergrad Proving Set Relationships: A-B ⊂ A & (A∩B)c = A∪Bc
Thank you very much for the correction. Well... there are no definitions, it just says let A, B and C be any set, prove that A\B⊂A.- Chis96
- Post #3
- Forum: Set Theory, Logic, Probability, Statistics
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Undergrad Proving Set Relationships: A-B ⊂ A & (A∩B)c = A∪Bc
Can some please explain to me how to solve these two questions? Let A, B and C be any sets, prove that: (a) A-B ⊂ A (b) (A∩B) complement = A complement ∪ B and (A∪B) complement = A complement∩ B complement.- Chis96
- Thread
- Relationships Set
- Replies: 8
- Forum: Set Theory, Logic, Probability, Statistics