Recent content by chris858

I get it now, so basically the equation i was using gave the total power watts, which is actually 6 not 2, and so there are 3 resistors, including the internal resistance, so therefore you have to divide 6 by 3 which gives 2.0Watts per resistor. Thankyou very much!

power is measured in watts current in amps resistance in ohms voltage in volts

power = work/time P=IV P=V²/R P=RI²

pwer= voltage times voltage over current. p=VxV/R so 12x 12/0.5=2

16+8=24 so 12/24=0.5A

flows through two resistors, total resistance = 16 ohms. Current = 12/16 =0.75A

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Homework Statement two 8 ohm resistors and a battery of emf 12.0V and internal resistance of 8ohms are connected in series. Calculate the power delivered to each external resistor and then calculate the power wasted due to internal resistance. I keep coming up with the answer 18 but apparently...