Recent content by chrisduluk

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    Geometric series convergence using Cauchy criterion and repeating decimals

    so do they want something like this? If I'm not using the .7171717, what will the beginning of my proof look like? Will be it to prove (a-ar^n+1)/(1-r) converges to a/(1-r)?
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    Geometric series convergence using Cauchy criterion and repeating decimals

    oh damn... yeah, i didn't use cauchy for that. I just did this. But I'm guessing i'll need cauchy. Wow, you're in europe! That's awesome, where i am in the US it's 10:43pm! If no one else chimes in, what should i do? Only because i need to get some sleep myself.. This assignment is due 6...
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    Geometric series convergence using Cauchy criterion and repeating decimals

    oh thank you! It doesn't involve cauchy, right?
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    Geometric series convergence using Cauchy criterion and repeating decimals

    if you can, yes please. I'm clueless.
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    Geometric series convergence using Cauchy criterion and repeating decimals

    so my proof looks good? :D
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    Geometric series convergence using Cauchy criterion and repeating decimals

    k, but if i pick my N as blah blah +1 i don't get a nice = E in the end. I get 1/100E. But if i just keep blah blah without the +1 it works out, like below:
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    Geometric series convergence using Cauchy criterion and repeating decimals

    and once i solve for N, how do i show that abs(Sn - thing it converges to) < E?
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    Geometric series convergence using Cauchy criterion and repeating decimals

    ok, so how would the "string of inequalities" look when i enter in big N? In all of the examples I've done, the string ended with something like if N=90/361E... 90/361n < 90/360N < 90/360(90/361E) = E but in this problem I'm not getting the last thing to be =E
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    Geometric series convergence using Cauchy criterion and repeating decimals

    but in post 50 i had 9900 as the denominator... should it be 9900 or 99?
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    Geometric series convergence using Cauchy criterion and repeating decimals

    yeah that was an error... if you only knew how much crap i have scattered around me right now... so is this how i write the proof? if not, can you point out or fix the errors?
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    Geometric series convergence using Cauchy criterion and repeating decimals

    can anybody tell me where my cauchy proof doesn't look right so i can fix it?? And how to i answer the "determine the conditions on a and r..." question?
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    Geometric series convergence using Cauchy criterion and repeating decimals

    on the scanned sheet, ignore the inequality, so N= everything to the right of the inequality sign. and you mean the floor function?
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    Geometric series convergence using Cauchy criterion and repeating decimals

    why can't i make my N= [ln(71/99E) / ln(100)] +1
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    Geometric series convergence using Cauchy criterion and repeating decimals

    Fredrik, I'm sorry but I'm not following you and i don't have any more time to work on this. I HAVE AN EXAM TOMORROW MORNING. I haven't even started studying for it yet because i keep running around aimlessly on this! I specifically posted on here to get HELP and I'm just getting more confused...
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    Geometric series convergence using Cauchy criterion and repeating decimals

    ...so what's that mean? huh? Can you just tell me what part of the N i calculated above is wrong? And how i can make it right? ie remove the denominator, add 1 to it, etc??
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