Recent content by cidr1337

That's what I am saying it's a program called mastering physics, that my university uses. and you're right about qb=q not mattering for the over all equation this program has given me a headache. I don't have my book i had been solving for the angle while solving for the force this whole time. I...

Can you guys help me figure out why qblue=q

Ok so the x component is (K*(2q^2)*cos(theta))/(d2^2). idk how they got qb=q if i could have gotten that I would have got the problem.

My problem is I went into the hints and the question asked me, "Find the x component of the force that the yellow sphere exerts on the blue sphere. Express your answer in terms of q, d2and theta. I input Fyonb and it tells me the answer doesn't depend on K or qb. It's telling me it's not right :(.

*That is my problem. I can't set this up. I tried 0=Fyonb+Fronb but my y on be expression is wrong. I don't know how to express this. Apparently it doesn't depend on K or qb, I said F yonb = (K*|2q|*|qb|)/(d^2)*cos(theta). I'm probably going to feel stupid when I figure this out. :)

Thanks for trying to help me guys.

Can you help me figure out the force that yellow exerts on blue? I think I'm having a problem with the actual equation. In the x direction? I'm saying it is Fyonb= (K*|2q|*|qb|)/(d2)^2cos(theta) but it says the answer doesn't rely on K or qb

shameless self bump.

Not sure i understand... sorry. My new attempt i set 0 = Fredonblue+Fyellowonblue 0=(K*qr*qb)/d1^2+ (k*qy*qb)/(d2cos(theta))^2 -(K*qy*qb)/(d2cos(theta))^2=(K*qr*qb)/d1^2 qb and K cancels out and setting qy=2q yields |qr|= -(2q(d1)^2)/(d2cos(theta))^2 does this make any sense or am i grabbing at...

yes.

in terms of q, theta, d1, and d2.

Homework Statement System with 3 charged particles red, yellow, and blue. The blue and red have a positive charge, while the yellow has a negative charge. The blue particle lies at (0,0). The red charge lies at (d1,0). The Yellow charge lies at (d2cos(θ), -d2sin(θ)). The Fon blue is (0,-F)...