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MHB Maximizing area of rectangular portion of athletic field
So we would have.. 2(x+pi*r)=200 (x+pi*r)=100 r=(100-x)/pi and after plugging it into A=2rx we would have the answer of... A= 2x((100-x)/pi) For part 2, I believe we take the first derivative of A= 2x((100-x)/pi), set it to 0 and solve for x. We would end up with x=50m. I just don't...- CinnamonStix
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- Forum: Calculus
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MHB Maximizing area of rectangular portion of athletic field
An athletic field is to be built in the shape of a rectangle x m long capped by semicircular regions of radius r m at the two ends. The field is to be bounded by a 200 m racetrack. Express the area of the rectangular portion of the field as a function of x alone. What value of x gives the...- CinnamonStix
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- Area Field Rectangular
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- Forum: Calculus