Recent content by CJoy
-
C
Thermodynamics - Change in temperature for heated slabs of steel
With the changes, does this look correct? Mass= 700kg x 4=2800kg Specific heat capacity of steel= 0.42kJ/kgC heat=70000kJ change in temp= temp final- temp initial temp initial=-250C change in temp= (70000)/(2800 x 0.42)=59.5C Temp final - temp initial= 59.5C Temp final - (-250C)=59.5C Temp...- CJoy
- Post #4
- Forum: Introductory Physics Homework Help
-
C
Thermodynamics - Change in temperature for heated slabs of steel
Just started this topic so I'm not sure if this is the correct way to solve this, any help would be appreciated. mass of object x change in temp x specific heat capacity= heat change in temp= heat/(mass of object x specific heat capacity) Mass= 700kg Specific heat capacity of steel= 0.42kJ/kgC...- CJoy
- Thread
- Change Steel Temperature Thermodynamics
- Replies: 3
- Forum: Introductory Physics Homework Help
-
C
Interactions and Potential Energy
Usps=1/2(1.8x10^6)(0.03)^2=810J Ke=1/2mv^2=1/2(0.05)(300)^2=2250J I don't know how to take it farther than this, or if this is the correct way to start the problem. If this is correct, would it be correct to assume that the bullet does penetrate the creature because Ke overcomes Usps?- CJoy
- Thread
- Energy Interactions Potential Potential energy
- Replies: 2
- Forum: Introductory Physics Homework Help
-
C
Mastering Motion on a Plane: Solving the Defiance Drake Question
This is the start of a new topic (Dynamics 2: Motion on a Plane) and I don't know how to start the problem- CJoy
- Thread
- Replies: 1
- Forum: Introductory Physics Homework Help
-
C
Kinematics in 1D: Will Defiance Drake reach the ship or miss?
0.25g converts into 2.45m/s^2 V(t)=Vo+AoT 1=0+2.45T T=1/2.45 T=0.4s X(t)=volt+1/2AoT X(t)=100+0+1/2(2.45)(0.4)^2 X(t)=100.196m I don't know if this is the right methodology or how to move on from here- CJoy
- Thread
- 1d Kinematics Ship
- Replies: 2
- Forum: Introductory Physics Homework Help