Recent content by Clay2

Great info, Or approx a 5-1 reduction gear @ approx 80 something overall efficiency? You need only 0.61 / 3.5 = 18% efficiency to make it work. So it's theoretically possible.

Okay, yea, that is what I have gotten from some other forums as well like: https://www.eng-tips.com/viewthread.cfm?qid=449391. PAT (pump as turbine). So, basically here is where the Physics comes in... That pressure/flow, 75psi min and 80 gpm min is what is available at the hose/inlet to PAT...

A pitot-tube pressure of at least 344 kilopascals (kPa) (50 pounds per square inch (psi)), and a flow rate of at least 300 liters per minute (lpm) (80 gallons per minute (gpm)); So we are talking about .3m^3/m @ about 50 psi. So approx 0.005 m^3/s. Looks like 50 psi is about 36 meters of head.

I am working on a design for a water powered drive shaft. The water source would be from a 2.5 inch diameter hose, at approx 75-100 psi. The goal would be to get 55-115 RPM from the shaft and max torque in the smallest possible handheld device. That being said, it seems my best options for...