Recent content by clhrhrklsr

how do you input that 41/22 in the calculator? How does that turn into the angle for L?

The opposite site is the 5' - 6". The adjacent side is the 10' 3". how would I input this into my hp 48g+?

Honestly, I'm not sure. I don't even know where to begin or how to start this. I apologize.

Someone please take a look at the attachment above. These two questions have me stumped and it ask on each question to find three missing angles. I don't even know where to start. Could someone be so kind and explain to me how to figure each of these. I need help with this asap to help my...

How would I work the following problem-19(degrees) 17' 33" - 7(degrees) 45' 28"Please help asap

On a 100' - 0" (100 feet 0 inches) long building, how many screws are required to screw gutter to the building 12" (12 inches) off center (O/C)? Could anyone tell me how this problem would be worked. And sorry there is not image to go by for this, as it is just a word problem. Thanks.

It was just a word problem on a practice test. Its a trick question I suppose to see if you can work the problem without a picture to go by.

No picture. Its just worded the way I typed it. I'm assuming a trick question.

That worked! Thank you. Now if you don't mind, lol, I need help on only one other problem. I am asked this on a practice question- On a 100' - 0" (100 feet 0 inches) long building, how many screws are required to screw gutter to the building 12" (12 inches) off center (O/C)?

That helped a lot. Here is where I got lost. $$\frac{10}{sin(23)} = c$$ How do I input the "sin(23)" in my calculator (HP 48G+)? I tried hitting 23 then my sin button and I get a weird decimal number. And then when I divide that by the 10, it lowers that decimal? Can you please tell me what I...

That would be great. I haven't went by any problems like these before and I'm trying to figure them out. I have never worked problems with the Law of sines before, and I wasn't sure how to even begin that second problem. Thanks

Please correct me if I'm wrong. \tan\left({67}\right) = \frac{AB}{BC} AB = 10 x \tan\left({67}\right) \tan\left({67}\right) = 23.5585 If you need to convert the decimal to feet and inches, you would get the following- 23.5585=23'-6\frac{11}{16}"

Thanks! I believe I'm on the right track. On page 2 of my attachment, I have a 2nd question. Here the practice question gives me 2 angles (90 degrees and 67 degrees). It also gives me a height of 10'-0". It asks if there is enough information given to find the length of side C (the slope of...

Thanks! Okay, now the 2nd question on my attachment. Is there enough information given to find the length of side C? You are given a 90 degree angle, a 67 degree angle. You are also given a height of 10'-0". Side "C" is the slope of the triangle. Is there enough information given in this...

I have a couple of practice problems similar to ones I've seen before. Could anyone tell me how to figure these? I don't even know where to begin on solving these. How do you begin to determine if you have enough information. Thanks in advance for any help!