Recent content by cmwestbr

And for number 3...i start by adding 90 degree + 12 degrees= 102, then 180-102=78 then i got lost when it asked for the ratio.

for question 2) would i use ∑F=ma...but i don't understand the part about constant speed?

ok so i understand in order to get the normal force u have to include gravity=9.8...

so what ima do is...6.67*10^-11(363kg)(517kg)/9.8^2...or is that not right?

Can someone help me with "The Normal Force" 1) Anyone know how to work out these problems? A 42 kg crate rests on a horizontal floor, and a 76 kg person is standing on the crate. (a) Determine the magnitude of the normal force that the floor exerts on the crate. (b) Determine the...

Could anyone help me with these problems? It's on Gravitational Force The drawing shows three particles far away from any other objects and located on a straight line. The masses of these particles are mA = 363 kg, mB = 517 kg, and mC = 154 kg. Find the magnitude and direction of the net...