Recent content by Cold As Ice

For Problem #41 the answer is 4.0 cm. The book only have odd. Yes, it will make it complicated. I do not know how to solve that way then. :frown:

7.8 as the book say. I don't know. Maybe it is typo? But look we used ds as one of the sides of triangle. But that ds is the entire height according what problem say. Also look I attached now again and marked it green line.

Ok. But that's not the right answer.

Wait. What sides you are saying? Can you explain in details. Thanks

Hmm. Thanks. So then 82.5/80 = 1.03125 1.03125 X 4 = 8.25 is the field size. But that is not right because d(s) is distance from the radiation source to the skin.

Well, I was not looking for a hypotenuse. I was just setting up the ratio. Well do you know how to solve this problem, because I have no clue at all.

I did read the explanatory paragraph. 80^2 + 4^2 = h^2 (82.5)^2 + (fd)^2 = (h2)^2 6806.25/6400 = 1.06 (ratio of two sides) 4 x 1.06 = 4.25 But this is not right since the ds = distance from the radiation source to the skin

Homework Statement Posted #39 and $41. (look at the attachment). ds = distance from the radiation source to the skin dt = distance from the outer layer of the skin to the targeted issue 2fs = field size of the skin 2fd = targeted field size Homework Equations None The...