Recent content by CONBOSS

Above poster SammyS said total mass was 550g, so I would assume to use 550g as my total mass for finding FNet right? I will fix the question when I write it out to make it more comprehensible!

For example: 3 Newtons [East30°North] + 5 Newtons [West] + 2 Newtons [West60°South]... Thanks! I missed the day we went over this in class so it is new to me!

Attempt; a) Given: Δd=1m, Δt=1.5s Δv= Δd/Δt Δv=1/1.5 Δv=.666 m/s a=Δv/Δt a=(.666/1.5) x 2 a=..888 m/s² Thus, acceleration of cart = .888 m/s² b) Given: Fapp = 0.49 N, mcart=.550 kg, a=.888 m/s² FNet= ma → (.550)(.888) FNet= .4882 FNet= Fapp + f + FN + Fg (FN & Fg are...

Easy N2L question... grade 11 physics Problem: A 500g dynamics cart is attached to a 50g mass, which is suspended over a pulley. When released from rest, it took 1.5 s for the cart to move a distance of 1m. Find: a) acceleration of cart, b) friction between cart and track...