Recent content by cranen

Thanks so much for all the help!

So I would need 20 total, or 10 if I used the very last equation I typed?

So it would be ## |B| = \frac μ 2 \frac {IR^2} {(R^2+z^2)^{3/2}} ## and then since there are two coils I would use just have ## |B| = μ \frac {IR^2} {(R^2+z^2)^{3/2}} ##

## |B| = \frac μ {4π} \frac {I*R^2*2π} {(R^2 + z^2)^(3/2)} ## R = 0.03 m z = d/2 = .065 m I = 3 A ## \frac μ {4π} = 1e-7 ##

I tried ## |B| = 1e-7*\frac {3A*0.03m^2*2π}{(0.03m^2+0.065m^2)^{3/2}} ## and then multiplied it by 2 to incorporate both rings and got 9.247e-6. It was wrong

Homework Statement Two thin coils of radius R = 3 cm are d = 13 cm apart and concentric with a common axis. Both coils contain 10 turns of wire with a conventional current of I = 3 amperes that runs counter-clockwise as viewed from the right side (see the figure). (a) What is the magnitude...