yes, I'm sorry but I'm basically trying to self teach myself since my teacher doesn't want to give examples.
Thank you so much for your help! I will attempt to write out my equations and formulas correct.
to get a number for friction i did : (0.4)(17.6*9.8)=68.992
0.4 being kinetic friction, 17.6 is total mass and 9.8 is gravity. 9.3 is pushing force fp
total forces= 0.04(9.8)(17.6)=.136
A= fp-f/m
a=9.3-.136/17.6=.521m/s^2
contact force =force-friction-ma
9.3-.136(7.0*.521)=5.517N
Im so sorry i...
Thank you, and i haven't grasped the concept of free body diagrams yet.
I tried the equation on a problem my tutor helped me with but i didn't get the same answer, What could be my fault?
if i get 9.3-6.9(7.0 * .136)= 1.448N
is this correct?
Homework Statement
Alex is asked to move two boxes of books in contact with each other and resting on a rough floor. He decides to move them at the same time by pushing on box A with a horizontal pushing force FP = 9.3 N. Here A has a mass mA = 10.6 kg and B has a mass mB = 7.0 kg. The contact...
Im cristina, and am currently taking physics 131 as a prereq for respiratory care. I'll try and participate in the forums but keep in mind i lack some knowledge. Thank you
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