Recent content by CSawyer717

  1. C

    Horizontal Force in Bottom Member of a Truss

    would that be the vertical component of AC if you made a FBD around point C? So, since you can just apply symmetry, you're able to assume only a 5kN downward force at C, and a force in member AC. then solving for Fac, you come up with Fac=5/cos(30), resulting in Fac=5.77kN. then summing...
  2. C

    Horizontal Force in Bottom Member of a Truss

    I have, and I'm still not understanding why you need to divide cos(60)/cos(30). Also, is that 10/2 from the one 10kN vertical force being split between the two members AC and BC? so when you draw your FBD about point A, you're only seeing half of that 10 kN force? i understand the cos(60) is the...
  3. C

    Horizontal Force in Bottom Member of a Truss

    Hello, I've been studying for the FE, and this question in the Statics section of the review I am going through has really tripped me up for some reason. I understand Statics, and how to determine forces in X and Y directions, determining X and Y components using trig, etc, etc.. Maybe I am...
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