My mistake. Its A= 2i+3j+k
AxB=-5i-2j+16k
abs(AxB) = 16.88
abs(AxB)=abs(A) x abs(B)sinθ
∴ abs(AxB)/(abs(A) x abs(B))= sinθ
∴ θ = 79.92
A.B=-3
A.B/(abs(A) x abs(B))= cos(theta)
∴θ = 100.08
The result of dot and cross product should be the same but its not in this case. Please help.
By using both cross and dot products, the angle between 2 vectors can be found. But there is 1 question that I tried for countless times that the result of cross product and dot product are not the same.
Here is the vectors that I am talking about
A= 2i+3j=k
B= -4i+2j-k
The result by...