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Finding the General Solution for a Second Order Differential Equation
Hi, I came across the following differential equation: \sqrt{1+(y')^2}=\frac{d}{dx}\left(y\frac{y'}{\sqrt{1+(y')^2}}\right) I found possible solutions: y\left(x\right)=cosh(x+C_{1}). However, this is a second order ODE so there exist a more general solution, with 2 freedom degrees...- Daniel D
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- Differential Differential equation General General solution Second order
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- Forum: Calculus and Beyond Homework Help