Recent content by DATAcrusher

But that would mean each AA battery would get about 2.1 amps through them. Due to their inner resistance, then they would heat up. Likely. However, I will try it out, but I'll wait until I get my multimeter- then I can make some diagrams, and check for all the important stuff you mentioned...

Of cause, I know how to solder stuff together, I was just very concerned about the high energy consumption in this circuit. The 30W got 30 diodes, the 100W got 100.. But they are close packed together. One thing I don't "get"- Why resistor between the [+] [R] [+Diode-] [-]

so you limit the 'I' in the entire circuit, and b/c the potential going over the resistor is 8 volts, we know that the diode will get the rest of the potential through it, and maximum 2.1 Amps. Right? D: IF IT'S RIGHT I'LL GIVE YOU A CUPCAKE!

dlgoff- 1. They were found on a Website. 2. I know I have to limit the current: If I have a "load" that's a LED, and luckily this does not require a voltage drop, Then I need to make use of U = I * R; U = 16 I = 2.1 therefore, R = 7.6 ohm however, doesn't this stress the limiting...

Okay, to cut a long story short, I got hold of a: 16~18V, 30W, White LED, 2100 milliamps. And a 32~36V, 100W, White LED, 3500 milliamps. I got some 6V lead batteries, and I would like to use them to make a crazy flashlight. I tried searching, I came upon quite a lot of solutions...