∫(dθ)/(a+bcosθ)^2
Homework Equations
I'm trying to find the above integral (from 0-2pi) using Cauchy's Residue theorem. After closing the contour and re-writing the integrant, I know that I have singularity at (-a/b)+(√(a/b)^2-1)- (double pole or is it??).
The Attempt at a Solution...