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Solving Second Pole Residue ∫(dθ)/(a+bcosθ)^2
∫(dθ)/(a+bcosθ)^2 Homework Equations I'm trying to find the above integral (from 0-2pi) using Cauchy's Residue theorem. After closing the contour and re-writing the integrant, I know that I have singularity at (-a/b)+(√(a/b)^2-1)- (double pole or is it??). The Attempt at a Solution...- davavsh
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- Pole Residue
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- Forum: Calculus and Beyond Homework Help