Recent content by david1111
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Energy conservation - maximun height and equilibrium height
is the total acceleration √(9.8^2 +31.3^2) =32.8 m/s^2 ? How can we be able to find Hmax then? I am completely lost.- david1111
- Post #6
- Forum: Introductory Physics Homework Help
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Projectile Motion Problem: Solving for Time and Velocity | Homework Help
Centripetal acceleration= v^2 / R? But, how to relate it and x?- david1111
- Post #4
- Forum: Introductory Physics Homework Help
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Energy conservation - maximun height and equilibrium height
Can we apply the equation mgh = Fs? However, it comes to the another question, how do we find s?- david1111
- Post #3
- Forum: Introductory Physics Homework Help
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Energy conservation - maximun height and equilibrium height
Homework Statement A ball of mass M = 0.320kg is connected by a light but rigid rod of length L = 0.770m to a pivot and held in place with the rod being vertical. A wind exerts a constant force F to the right on the ball. The ball is released from rest, and the wind makes it swing up to a...- david1111
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- Conservation Energy Energy conservation Equilibrium Height
- Replies: 12
- Forum: Introductory Physics Homework Help
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Projectile Motion Problem: Solving for Time and Velocity | Homework Help
Homework Statement Homework Equations R = 1/2 gt^2 R+x = vt The Attempt at a Solution For a), I tried to find t first, which is equal to √(2R/g). Then, I put t = √(2R/g) into the equation R+x = vt, and I found out that v = (R+x)/√(2R/g), is that correct? For b), is the...- david1111
- Thread
- Motion Projectile Projectile motion
- Replies: 5
- Forum: Introductory Physics Homework Help