Recent content by DCC01

So I get a pair of simultaneous equations for h: (1) h=(d)tan(theta)-(d)²(g/2u²)(1+tan²(theta)) (2) h=(2d)tan(theta)-4(d)²(g/2u²)(1+tan²(theta)) Multiply (1) by -4: (1a) -4h=(-4d)tan(theta)+4(d)²(g/2u²)(1+tan²(theta)) Add (1a) and (2): (3) -3h=(-2d)(tan(theta)) as required...

Homework Statement A projectile is launched from O with speed u at angle theta to the horizontal. In its subsequent trajectory it just clears two obstacles of height h at horizontal distances d and 2d from O, respectively. http://img403.imageshack.us/img403/4369/projectile.jpg Show...