Sorry, the problem is, I haven't learned integration yet, so I can't use it. But I think I might have it using another method.
If \frac{dx}{dt}=.2222yd2/sec, I could substitute into the derivative, \frac{dy}{dt}=5\frac{dx}{dt} to get \frac{dy}{dt}=1.1111 lbs/sec. So its saying that tar paper...