Right, I meant converge...
magnetic field inside a long cylindrical conductor with radius R (r: distance to axis): B = \frac{\mu_0 I \cdot r}{2 \pi R^2}
Thank you so much! Yes, in the original question there are 2 long copper cylinders, but since it was a 2-part question, I thought that detail was irrelevant for the fist part (second part is on how much magnetic energy is left 20µs after turning off the power source). My course is in Dutch...
Homework Statement
Given a rectangular loop of length C by length D (C >> D) through which a current I flows, calculate the self-inductance L of the loop (consider only the long sides of the rectangle).
Homework Equations
Self-inductance: L = \frac{N \cdot \Phi_B}{I}
magnetic flux: \Phi_B =...