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Self-inductance of a rectangular loop
Right, I meant converge... magnetic field inside a long cylindrical conductor with radius R (r: distance to axis): B = \frac{\mu_0 I \cdot r}{2 \pi R^2}- De_Lille_D
- Post #5
- Forum: Advanced Physics Homework Help
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Self-inductance of a rectangular loop
Thank you so much! Yes, in the original question there are 2 long copper cylinders, but since it was a 2-part question, I thought that detail was irrelevant for the fist part (second part is on how much magnetic energy is left 20µs after turning off the power source). My course is in Dutch...- De_Lille_D
- Post #3
- Forum: Advanced Physics Homework Help
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Self-inductance of a rectangular loop
Homework Statement Given a rectangular loop of length C by length D (C >> D) through which a current I flows, calculate the self-inductance L of the loop (consider only the long sides of the rectangle). Homework Equations Self-inductance: L = \frac{N \cdot \Phi_B}{I} magnetic flux: \Phi_B =...- De_Lille_D
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- Loop Rectangular
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- Forum: Advanced Physics Homework Help