I have three signals in the aromatic region that accounts for 5 hydrogens. There is only one more signal of three hydrogens. It must be a CH3 group. so this gives me
C6H5 + CO2 + CH3?
so I'm only thinking of C6H5-COOCH3 which is a methyle benzoate...
Hi all,
I was struggling in solving this question which is a part of a practice exam, and I need you to be patient with me and teach me step by step how to figure out the structure and how to read and analyze the spectra.
I attached the two 1H NMR & IR spectra so you will be able to know...