Recent content by Dellis

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    [Guidance needed]-Compute the Magnitude and Direction of the Resultant Couple

    Oh so its just about stating the direction, I guess I can talk to him about it but I would put "out of page" in this case right?, that's what I vision it doing. I was just throwing that out there in the myst of confusion, sorry... Oh ok, thanks for clearing that up :)
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    [Guidance needed]-Compute the Magnitude and Direction of the Resultant Couple

    You open everything by turning to the left, so it moves in the left direction. Do I just state it like that with words or would I need to do something like this? \SigmaF= F1 + F2+ F3 + F4 30lb + 50 + 30+ 50= Or Is that^ just a wrong turn?... What's confusing me is that it...
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    [Guidance needed]-Compute the Magnitude and Direction of the Resultant Couple

    It will do a circular motion TO THE LEFT, the force of 30 lb will push to the left and then the bigger force of 50lb will make the whole rotation happens. Is that a good way of seeing it?, I would need to show that in a calculated manner thought?, since it does say "compute the magnitude(done)...
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    [Check for errors]- FREE BODY DIAGRAM for 2 Cylinders.

    ah ok, I will make sure to tell the teacher that, he has never said that in class.hey can you help me out in the other thread, dealing with Circle with forces, asking to compute the magnitude( which I did already ) and direction of the resultant couple acting on the body.( I don't get this part...
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    [Check for errors]- FREE BODY DIAGRAM for 2 Cylinders.

    Keep in mind this a basic FBD and the teacher said he wanted to see all the given info portrayed in the FBD, nothing about equations or nothing like that, he just wants to see a F.B.D. and that's it.
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    [Guidance needed]-Compute the Magnitude and Direction of the Resultant Couple

    Seems like Jay went offline... Can another helper chime in please, specially about the whole direction part of the exercise.He said I got this part of the process goodM= 50(3)+50(3)+30(3)+30(3) M= 50(6)+ 30(6)= 480 ft-lbThe next step is about direction and he said something there I did not...
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    [Check for errors]- FREE BODY DIAGRAM for 2 Cylinders.

    Ah ok, I was just making sure, I mean the problem here has specific Kg masses for each of the Cylinders, so I was just making sure wondering why you didn't use the given Kg mass, clearly I need to use them though.
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    [Check for errors]- FREE BODY DIAGRAM for 2 Cylinders.

    I noticed you used Mg for the Weight, you did that as an example or I am missing something here?, I thought for a F.B.D. you show what is given to you?, no conversions or anything like that needs to be done.
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    [Check for errors]- FREE BODY DIAGRAM for 2 Cylinders.

    Oh no I got that much, I was just wondering how it was presented because I never seen anything like that before, but like I said before we never did these types in class all we done is beams with Pins and Weights on them. Anyways, thanks for clearing that up and helping me understand while also...
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    [Check for errors]- FREE BODY DIAGRAM for 2 Cylinders.

    Thanks for clearing that up, I do have a question, Can you explain how in Cylinder A got reaction up and down in the same route? I never seen that in class, then again we never did this type of exercise in class just beams.
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    [Check for errors]- FREE BODY DIAGRAM for 2 Cylinders.

    Here is the edited picture, with your advise taken into account, I am not sure if I am missing any other reactions, You did say something about missing the reaction form the ground?, perhaps my edited still pic is still wrong but check out and provide further guidance please.
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    [Check for errors]- FREE BODY DIAGRAM for 2 Cylinders.

    1- Well thanks to your drawing I figured that's what I missed there 2- I drew them like I did because I am going by the reaction of the Cylider, you're showing me that it needs to be the other areas reaction with the Cylinder 3. Yeah part 2 pretty much explains that I didn't follow the...
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    [Check for errors]- FREE BODY DIAGRAM for 2 Cylinders.

    What do you mean?, the reaction from the group UP^?
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    [Check for errors]- FREE BODY DIAGRAM for 2 Cylinders.

    Wait with what you said there and even posted a pic, I can assume that the Cylinder B also needs a Force from the right like this <------ and not like I have it which is like -------> correct? or I am I looking too deep into it??
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