Demystifier's latest activity

In order to better explain all this to myself (and hopefully to others as well), I will present a simple toy model. Consider two point...

@Dale and @PeterDonis I'm still somewhat confused, so I will ask a slightly more general question. Consider a Newton-like theory of...

Yes, that is what I mean. I will point out that we are having this conversation in the Special and General Relativity subforum, so...

I still disagree to some level. If we define force as mass times acceleration, the acceleration is always relative to a specified...

That works for a macroscopic body, but not for a microscopic particle.

How would you measure the electric force, without a reference to a frame? Note that the Coulomb theory of electric force is almost...

I think we disagree on what does it mean to measure something. In my view, to measure something means to infer it from observing...

E.g. by weighing scale.

As Einstein said, it is theory which determines what is measurable. According to the Newtonian theory of gravity, the gravitational...

Well, for those who like Albert's style of writing, it's probably good. Personally I'm not a fan of his style, but I believe there is...

I finished browsing Albert's "Quantum Mechanics and Experience" book, and studying its last chapter "8. Self-Measurement", where his...

The Albert's Chapter 8 is very interesting on its own right. It considers a version of the Wigner's friend thought experiment, by which...

On the other hand, a particle model is, itself, an approximation. If you believe QFT, there are only continuous fields at the root. And...

The geodesic equation $$\frac{d^2x^{\mu}}{d\tau^2} + \Gamma^{\mu}_{\alpha\beta} \frac{dx^{\alpha}}{d\tau} \frac{dx^{\beta}}{d\tau} = 0$$...

If you right-click on the equation in my post, you can see the ##\LaTeX##-code used to create it.