Recent content by Dern

After tilting the axes to fit the 10 degree down ramp, I first found the tilted y distance drop that corresponds with the 20 m vertical drop: y = -20cos(10) = -19.7 m. Then I used the formula, y = v(i,y)t + 1/2a(y)t^2, to get: -19.7 = 0*t + 1/2(-9.8cos(10))t^2 since the initial velocity is...