So: Given: 1min = 60sec = t// 5.0l = volume of water= 5kg = m // ΔT = 35°C // V = 230V //
Asked: R & I
Answer: Q = c . m . ΔT
Q = 4186 . 5 . 35
Q = 732550 J/kg . K
I = Q/ t
I = 732550/ 60
I = 12209.17 A
I don't even need to continue...
This is the question: You want to make an electric instantaneous water heater in which 5.0 liters of water flows past a resistance per minute and heats water from 10.0 ° C to 45.0 ° C. Calculate the magnitude of the resistance to use and the amperage. The flow-through is connected to 230V
So...