Recent content by Diana Dobleve

Ooh duh. Okay, now I just have two small questions. So when I differentiate both sides I'm getting: (d/dx)(1/y) = -1 - 2(sinx/cosx) - (2x+1)/((x^2)+x+1). I don't know how to differentiate the 2 in front of the ln, or am I not suppose to differentiate it? And I don't know how to handle...

I understand all of that except how you got 2ln(cos(x)). What rule is that? Or do you have a source I can look at to see why that is?

Okay, thanks, but I would still have a ln(cosx^2) by doing that right? It would become lne^-x + ln(cosx^2). (cos^2x means the same thing as cosx^2 right? Or do I need to specifically write ((cos^2)x)?

Homework Statement 1) I am having trouble with the questions, "Use the logarithmic derivative to find y' when y=((e^-x)cos^2x)/((x^2)+x+1) Homework Equations (dy/dx)(e^x) = e^x (dy/dx)ln(e^-x) = -x ? The Attempt at a Solution First I believe I put ln on each set of terms (Though I don't know...