Recent content by Digital Genius

ok thanks haha, i have it now, i even checked with my A- standard student/friend :D

ok well according to my friends its this, but i don't see where they multiplied and divided... =√99+1 - √r =√99+1 -√1 =√100 - √1 =10-1 =9 any ideas??

so what is the rest of it that you got? because I am stumped haha

ok nevermind guys sorry, i just found that i did do the question haha... anyways for those who want to know its like this... T1, T2, T3 1/a, 1/b, 1/c = AS T2-T1=T3-T2 T2+T2=T3+T1 1/b + 1/b = 1/c + 1/a 2(1/b)=1/ac 2b=1/(1/a - 1/c) b= 2 1/(1/a - 1/c) and that's it i think..

Homework Statement Evaluate: 99 ∑ 1 over √r+1 + √r r=1 Homework Equations this might be relevant.. the previous question was this, which i managed to solve but it still has the same fraction in it. Show that: 1 over √r+1 + √r = √r+1 - √r , for r is greater or equal to 0...

Homework Statement * "/" means divided by * 1/a , 1/b , 1/c are consecutive terms in an AS, where a,b,c ε R\0. (whatever that means haha) express b in terms of a and c. give your answer in its simplest form. *thats all it says* Homework Equations there are none :) The...

Homework Statement a, b and c are consecutive numbers in a geometric sequence, where a+b ≠ 0 and b+c ≠ 0 * "/" means divide * Show that 2ab/a+b, b and 2bc/b+c are consecutive terms in an arithmetic sequence The Attempt at a Solution i know this has something to do with it...