Recent content by dipluso

Duh, figured it out. For y=ln(x), error dy=dx/x since lob(x) base b = ln(x)/ln(b) Then for y=lob(x) base b , error is dy=(1/ln(2))(deltax/x) Done. Cheers, -Alex

Hi, I am trying to represent my data in log2 form rather than "fold change" and I am embarrassed to say I can't remember how convert the error. For example, I have x=3.96 (mean), deltax=0.28 (standard dev). Thus, log2(x)=0.598. But how do I convert the error?? I know how to do it for...

Thanks to you both. I have to say that you both give very reasonable answers - and indeed they report similar errors. I don't know why the value reported by the machine's software is different (mine was just plain wrong). Indeed it may be that it takes so other invisible factor into account...

Hi, I've been trying to reproduce the output of an analytical machine here at work by doing the calculation myself in Excel but I can't get the error to match. Perhaps I am propagating the error incorrectly... The calculation is z = 2^(x-y) The values are: x = 24.96 y = 25.98 and...