Recent content by donaldduck

Thanks Clamtrox! So I meant to write: ∫sin(x)e^Cos(x) dx = ∫-e^u du =-e^u +c =-e^cos(x) +c

So a question for a test I just had was integrate by substitution: Sin(x)e^Cos(x). I did something like this: Let u=Cos(x) du=-sin(x) dx ∫sin(x)e^Cos(x) dx = ∫-e^u du =∫-e^Cos(x) du...