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[b]1. A boulder initially at rest rolls down a hill with an acceleration of 3.69m/s^2. If it accelerates for 7.72 seconds, how far will it move? [b]2. d=v0(initial velocity)t+.5at^2 [b]3. d=(0)(7.72)+.5(-9.8)(3.27)^2 -39.24+-52.4 -91.64m